Решить 1) 2sin^2х - 3cosx - 3 = 0 [п; 3п] 2) 1/cos^2x + 4tgx - 6 = 0 [2п; 7п/2] 3) 6cos2x - 14cos^2x - 7sin2x = 0 [-3п/2;

Question

Алгебра: Решить 1) 2sin^2х - 3cosx - 3 = 0 [п; 3п] 2) 1/cos^2x + 4tgx - 6 = 0 [2п; 7п/2] 3) 6cos2x - 14cos^2x - 7sin2x = 0 [-3п/2; -п/2]

bebe13 · Answer

Решение второго уравнения в приложении...

Решить 1) 2sin^2х - 3cosx - 3 = 0 [п; 3п] 2) 1/cos^2x + 4tgx - 6 = 0 [2п; 7п/2] 3) 6cos2x - 14cos^2x - 7sin2x = 0 [-3п/2; -п/2]