Решить log(x-2)> 1 b log1/2< -1

Log(x-2)>1
ОДЗ: x-2>0; x>2

log10(x-2)>log10 10
x-2>10
x>12

x>12

log10(1/2 * x)<-1
ОДЗ x/2>0; x>0
log(1/2 * x)<-1
log10(x/2)<log10(1/10)
x/2<1/10
x<1/5

x∈(0;1/5)