Сколько грамов будет весить 112 литров сероводород в нормальных условиях
Neralyda
3
28.05.2019 07:40
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2
m(H2S) = 5*34=170г m=n*M(Mr) M=Mr Mr(H2S) = 34 М= 34г/моль
ответ: 170г