[OH-]=2*C{Ca(OH)2} = 2*0.01 =0.02 M
[H+] = Kw / [OH-] = 10^-14 / 0.02 = 5*10^-13
pH = - lg(5*10^-13)=12.3
[OH-]=2*C{Ca(OH)2} = 2*0.01 =0.02 M
[H+] = Kw / [OH-] = 10^-14 / 0.02 = 5*10^-13
pH = - lg(5*10^-13)=12.3