Na2SO4+BaCL2=BaSO4+2NaCl
m(Na2SO4)=150*0.2=30г
n(Na2SO4)=n(BaSO4)=30/142=0.2113моль
m(BaSO4)=0.2113*233=49.2 г
Na2SO4+BaCL2=BaSO4+2NaCl
m(Na2SO4)=150*0.2=30г
n(Na2SO4)=n(BaSO4)=30/142=0.2113моль
m(BaSO4)=0.2113*233=49.2 г