дано
m(ppa KCL) = 200 g
W(KCL) = 30%
+V(H2O)= 150 ml
W1(KCL)-?
m(KCL) = 200*30% / 100% = 60 g
m(H2O) = p(H2O) * V(H2O) = 1*150 = 150 g
m1(ppa KCL) = m(ppa KCL) + m(H2O) = 200+150 = 350 g
w1(KCL) = 60 / 350 * 100% = 17.14%
ответ 17.14 %
дано
дано
m(ppa KCL) = 200 g
W(KCL) = 30%
+V(H2O)= 150 ml
W1(KCL)-?
m(KCL) = 200*30% / 100% = 60 g
m(H2O) = p(H2O) * V(H2O) = 1*150 = 150 g
m1(ppa KCL) = m(ppa KCL) + m(H2O) = 200+150 = 350 g
w1(KCL) = 60 / 350 * 100% = 17.14%
ответ 17.14 %