Найти удлинение пружины жесткостью 500 н/кг если к ней подвесить груз массой 1500г
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30.04.2019 09:48
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3
Fупругости=k(l1-l2)
Пружина в равновесии:
Fупругости=mg
m=1500г=1,5кг
Отсюда:
mg=k(l1-)2)
l1-l2=(mg)/k=15/500=0,03 м
ответ: 0,03 м