Выполните действие: 1) 2m-20/m^2-4+4/m-2-6/m 2) 1/x+3 - x^2+18/x^3+27

(2m-20)/(m-2)(m+2) +4/(m-2) -6/m=(2m²-20m+4m²+8m-6m²+24)/m(m²-4)=
=(24-12m)/m(m-2)(m+2)=12(2-m)/m(m-2)(m+2)==-12/m(m+2)
2)1/(x+3)-(x²+18)/(x+3)(x²-3x+9)=(x²-3x+9-x²-18)/(x+3)(x²-3x+9)=-3(x+3)/(x+3)(x²-3x+9)=
=-3/(x²-3x+9)==3/(3x-x²-9)