Решите уравнение (х-4)(х+-5)(х-6)=3х 12х^2-(3х-4)(4х+1)=19

1)(x-4)(x+2)-(x-5)(x-6)=3x
xˇ2-2x-8-xˇ2+11x-30=3x
9x-38=3x, 6x=38, x = 19/3
2)12xˇ2 - (3x-4)(4x+1)=19
12xˇ2- (12xˇ2-13x-4)=19
12xˇ2-12xˇ2 +13x+4 = 19
13x =15, x=15/13