Решите уравнение (4x^2+3) (5x-2)+(4x^2-3) (5x-2)=40x^3+6x

(4x^2+3) (5x-2)+(4x^2-3) (5x-2)=40x^3+6x

(5х-2)(4x^2+3+4x^2-3) =40x^3+6x


(5х-2)(8x^2) =40x^3+6x

(40х^3-16x^2) =40x^3+6x

40х^3-16x^2-40x^3-6x=0

-16x^2-6x=0
x=0 или -16х-6=0
х=0 или х=-6/16=-3/8