Решите системы, 30 5)4х^2+y=9 8x^2-y=3 6) 3x^2+y=4 2x^2-y=1 7)2x^2+y=4 4x^2-y=2 8)5x^2+y=12 9x^2-y=2

Zhans111 Zhans111    3   18.03.2019 20:17    1

Ответы
DashaP2006 DashaP2006  26.05.2020 00:58

5)+\left \{ {{4x^{2}+y=9 } \atop {8x^{2}-y=3 }} \right.\\ --------\\12x^{2}=12\\\\x^{2}=1\\\\x_{1} =-1\\\\x_{2}=1

\left \{ {{x=-1} \atop {y=9-4*(-1)^{2} }} \right. \\\\\left \{ {{x=-1} \atop {y=5}} \right.\\\\\left \{ {{x=1} \atop {y=9-4*1^{2} }} \right.\\\\\left \{ {{x=1} \atop {y=5}} \right.

ответ : (- 1 ; 5) , (1 ; 5)

6)+\left \{ {{3x^{2}+y=4 } \atop {2x^{2}-y=1 }} \right.\\\\-------\\5x^{2}=5\\\\x^{2}=1\\\\x_{1}=-1\\\\x_{2}=1\\\\y_{1}=4-3*(-1)^{2}=1\\\\y_{2}=4-3*1^{2} =1

ответ : (- 1 ; 1) , (1 ; 1)

7)+\left \{ {{2x^{2}+ y=4} \atop {4x^{2}-y=2 }} \right.\\ --------\\6x^{2} =6\\\\x^{2}=1\\\\x_{1}=-1\\\\x_{2}=1\\\\y_{1} =4-2*(-1)^{2}=2\\\\y_{2}=4-2*1^{2}=2

8)+\left \{ {{5x^{2}+y=12 } \atop {9x^{2}-y=2 }} \right.\\ --------\\14x^{2}=14\\\\x^{2}=1\\\\x_{1}=-1\\\\x_{2}=1\\\\y_{1}=12-5*(-1)^{2}=7\\\\y_{2}=12-5*1^{2}=7

ответ : (- 1 ; 7) , ( 1 ; 7)

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