Решить квадратные уравнения: (через дискриминант) 1) 4x^2-2x+3=0 2) 7x^2-28=0 3) 3x^2-5x+2=0 4) x^2-2x=0 5) 121-x^2=0

1) 4x^2-2x+3=0

Д = 4 - 4 * 4 * 3 = 4 - 48 = -44 < 0 нет корней

2) 7x^2-28=0

Д = 0+4*7 * 28 = 28²

х(1) = 0 - 28 / 14 = -2

х(2) = 0+28 / 14 = 2

3) 3x^2-5x+2=0

Д = 25 - 4*3*2 = 24-24 = 1 = 1²

х(1) = (5+1) / 6 = 6/6 = 1

х(2) = (5-1) / 6 = 4/6 = 2/3

4) x^2-2x=0

Д = 4 - 0 = 4 = 2²

х(1) = (2-2) / 2 = 0

х(2) = (2+2) / 2 = 2

5) 121-x^2=0

х² -121 = 0

Д = 0 + 4*121 = 484 = 22²

х(1) = (0+22) / 2 = 11

х(2) = (0-22) / 2 = -11