Найдите производную 1) x/3 - 7/2x^2 + 10 2) 4x^2 - 7/x^2 3) (5-9x)^4

1) x/3 - 7/2x^2 + 10   y'=(x/3)'-(7/2x^2 )+(10)'=1/3-7/2*x⁻²'+0
-7/2(x⁻²)'=+2*7/2x⁻³=7/x³   y'=1/3+7/x³ 

2) (4x^2 - 7/x^2)'=8x+7*2*x⁻³=8x+14/x³

3) [(5-9x)^4]'=4(5-9x)³*(5-9x)'=-36(5-9x)³