14(2у-3)-5(у+4) = 2(3у+5)+5у;
28y - 42 - 5y - 20 = 6y + 10 + 5y;
28y - 5y - 6y - 5y = 10 + 42 + 20;
12y = 72;
y = 6;
14(2у-3)-5(у+4) = 2(3у+5)+5у;
28y - 42 - 5y - 20 = 6y + 10 + 5y;
28y - 5y - 6y - 5y = 10 + 42 + 20;
12y = 72;
y = 6;
28у-5у-6у-5у=10+42+20
12у=72
у=72:12
у=6
ответ: 6