(log3)(log3+logx)=(log4)(log4+logy)and(logx)(log4)=(logy)(log3)
logy=log4log3logx
(log3)(log3+logx)=(log4)(log4+log4log3logx)
(log3−(log4)2log3)logx=(log4)2−(log3)2
logxlog3=−1
logx=−log3=log(1/3), so that x=1/3.
(log3)(log3+logx)=(log4)(log4+logy)and(logx)(log4)=(logy)(log3)
logy=log4log3logx
(log3)(log3+logx)=(log4)(log4+log4log3logx)
(log3−(log4)2log3)logx=(log4)2−(log3)2
logxlog3=−1
logx=−log3=log(1/3), so that x=1/3.