Log 4/√3 + √7 по основанию √2 + log1/ 10 + 2√21 по основанию 0,5 !

Log√₂(4/(√3+√7)+₀,₅(1/(10+2√21)=log₂^(¹/₂)(4/(√3+√7)+log₂⁻¹(1/(10+2√21)=
=2*log₂(4/(√3+√7)-log₂(1/(10+2√21)=log₂(4/(√3+√7)²-log₂(1/(10+2√21)=
=log₂(16*(10+2√21)/(3+2√21+7)=log₂(2⁴*(10+2√21)/(10+2√21)=
log₂2⁴=4.