2x²-5x-3=0
Δ=(-5)²-4*2*(-3)Δ=25+24
Δ=49
√Δ=7
x₁=(-(-5)-7)/(2*2)x₁=-2/4
x₁=1/2
x₂=(-(-5)+7)/(2*2)x₂=12/4
x₂=3
2x²-5x-3=0
Δ=(-5)²-4*2*(-3)
Δ=25+24
Δ=49
√Δ=7
x₁=(-(-5)-7)/(2*2)
x₁=-2/4
x₁=1/2
x₂=(-(-5)+7)/(2*2)
x₂=12/4
x₂=3