f(x)=6Vx^3-5x
f'(x)= 3(3x^2-5)/V x^3-5x =0
3x^2-5=0
x=+-V5/3
ответ +- V5/3
y'(pi/6) = 1/4cos^2(pi/6) =3/16
tga=3/16
a=arctg(3/16)
f(x)=6Vx^3-5x
f'(x)= 3(3x^2-5)/V x^3-5x =0
3x^2-5=0
x=+-V5/3
ответ +- V5/3
y'(pi/6) = 1/4cos^2(pi/6) =3/16
tga=3/16
a=arctg(3/16)