1)bc+3ac-2ab-6(a^2)=b(c-2a))+3a(c-2a)=(c-2a)(b+3a)
2.z-3(z^2)+(z^3)-3=z^2(z-3)+z-3=(z-3)(z^2+1)
3.2(b^3)-6-4(b^2)+3b =2b^2(b-2)+3(b-2)=(b-2)(2b^2+3)
1)bc+3ac-2ab-6(a^2)=b(c-2a))+3a(c-2a)=(c-2a)(b+3a)
2.z-3(z^2)+(z^3)-3=z^2(z-3)+z-3=(z-3)(z^2+1)
3.2(b^3)-6-4(b^2)+3b =2b^2(b-2)+3(b-2)=(b-2)(2b^2+3)