1/(x-2)² - 1/(x-2) - 6= 0
одз x≠2
1/(x-2) = t
t² - t - 6 = 0
D = b² - 4ac = 1 + 24 = 25
t12 = (1 +- 5)/2 = 3 -2
1. t = 3
1/(x - 2) = 3
3x - 6 = 1
x = 7/3 = 2 1/3
2. t = -2
1/(x - 2) = -2
1 = 4 - 2x
x = 3/2 = 1 1/2
ответ 7/3 3/2
1/(x-2)² - 1/(x-2) - 6= 0
одз x≠2
1/(x-2) = t
t² - t - 6 = 0
D = b² - 4ac = 1 + 24 = 25
t12 = (1 +- 5)/2 = 3 -2
1. t = 3
1/(x - 2) = 3
3x - 6 = 1
x = 7/3 = 2 1/3
2. t = -2
1/(x - 2) = -2
1 = 4 - 2x
x = 3/2 = 1 1/2
ответ 7/3 3/2