1)
2) 2a^2 - 5ab + 2b^2 = a^2 - 4ab + 4b^2 + a^2 - ab - 2b^2 = (a-2b)^2 + (a-2b)(a+b) = (a-2b)(a-2b+a+b) = (a-2b)(2a-b)
При a = √7+√6; b = √7-√6 получается:
2a^2 - 5ab + 2b^2 = (a-2b)(2a-b) = (√7+√6-2√7+2√6)(2√7+2√6-√7+√6) = (3√6-√7)(3√6+√7) = 9*6 - 7 = 54 - 7 = 47
3)
4)
1)
2) 2a^2 - 5ab + 2b^2 = a^2 - 4ab + 4b^2 + a^2 - ab - 2b^2 = (a-2b)^2 + (a-2b)(a+b) = (a-2b)(a-2b+a+b) = (a-2b)(2a-b)
При a = √7+√6; b = √7-√6 получается:
2a^2 - 5ab + 2b^2 = (a-2b)(2a-b) = (√7+√6-2√7+2√6)(2√7+2√6-√7+√6) = (3√6-√7)(3√6+√7) = 9*6 - 7 = 54 - 7 = 47
3)
4)