Пошаговое объяснение:
f(x) – f(x₀) = f (x₀ +Δx) – f(x₀).
А)f(x)=4/х, x₀ =-2 ,Δх=0,5
Δf= f(-2+0,5) – f(-2) = f (-1,5) – f(-2)=
=4/(-1,5)+4/2= -4/1,5+4/2=
=(-8+6)/3=-2/3;
Б)f(x)= х²-2х+2, x₀ =3 ,Δх=-2,6.
Δf= f(3-0,2) – f(3) = f (2,8) – f(3)=
=2,8²-2*2,8+2-( 3²-2*3+2)=
=7,84-5,6+2-9-6-2=-12,76.
В)f(x)= х²+3х, x₀ =-2,5 ,Δх=-2,6.
Δf= f(-2,5-2,6)– f(-2,5) = f (-5,1) – f(-2,5)=
= (-5,1)²-3*5,1-( (-2,5)²-2*2,5)=
=26,01-15,3-(6,25-5)=10,71-1,25=9,46
Пошаговое объяснение:
f(x) – f(x₀) = f (x₀ +Δx) – f(x₀).
А)f(x)=4/х, x₀ =-2 ,Δх=0,5
Δf= f(-2+0,5) – f(-2) = f (-1,5) – f(-2)=
=4/(-1,5)+4/2= -4/1,5+4/2=
=(-8+6)/3=-2/3;
Б)f(x)= х²-2х+2, x₀ =3 ,Δх=-2,6.
Δf= f(3-0,2) – f(3) = f (2,8) – f(3)=
=2,8²-2*2,8+2-( 3²-2*3+2)=
=7,84-5,6+2-9-6-2=-12,76.
В)f(x)= х²+3х, x₀ =-2,5 ,Δх=-2,6.
Δf= f(-2,5-2,6)– f(-2,5) = f (-5,1) – f(-2,5)=
= (-5,1)²-3*5,1-( (-2,5)²-2*2,5)=
=26,01-15,3-(6,25-5)=10,71-1,25=9,46