Тема: квадратные уравнения, решить 5-4x^2-x=0
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27.09.2019 07:50
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5-4x^2-x=0
-4x^2-x+5=0
4x^2+x-5=0
D=1-4*4*(-5)=81
x1=(-1+9)/8=8/8=1
x2=(-1-9)/8=-10/8=-1.25