Сос решите уравнение: (х-2)(х-3)(х-4)=(х-2)(х-3)(х-5) огэ, часть 2

(x - 2) (x - 3) (x - 4) = (x - 2) (x - 3) (x - 5)

x^3 - 9 x^2 + 26 x - 24 = (x - 5) (x - 3) (x - 2)

x^3 - 9 x^2 + 26 x - 24 = x^3 - 10 x^2 + 31 x - 30

x^2 - 5 x + 6 = 0

(x - 3) (x - 2) = 0

x - 3 = 0 or x - 2 = 0

x = 3 or x - 2 = 0

x = 3 или x = 2