Решите уравнения: 1) (4/25)^х+2=(5/2)^6 2) 3^2х+1 + 3^2х+3=10 !

1) ( 4/25 ) ^ X + 2 = ( 5/2 ) ^ 6 ; ( 2/5 ) ^ 2x + 4 = ( 2/5 ) ^ - 6 ; 2x + 4 = - 6 ; 2x = - 10 ; X = - 5 ; 2) 3 ^ 2x + 1 + 3 ^ 2x + 3 = 10 ; 3 ^ 2x * ( 3 + 27 ) = 10 ; 3 ^ 2x = 10 : 30 ; 3 ^ 2x = 3 ^ - 1 ; 2x = - 1 ; X = - 0,5