Решите уравнение: sin2x-4sin^2x=0 .

Sin 2x - 4sin^2 x = 0
2sin x*cos x - 4sin^2 x = 0
2sin x*(cos x - 2sin x) = 0
1) sin x = 0; x1 = pi*k
2) cos x = 2sin x
sin x/cos x = tg x = 1/2
x2 = arctg(1/2) + pi*n