Решите уравнение (5×+2)^2=(5×-3)(4×+1)

25х^2 + 20x + 4 = 20x^2 - 12x + 5x - 3
25x^2 + 20x + 4 - 20x^2 +7x  + 3 = 0
5x^2 + 27x + 7 = 0
D = 729 - 4*5 *7 = 729 - 140 = 589;   √D ≈ 24,27
x1 = (-27 + 24,27) / 10 = - 2,63/10 = - 0,263
x2 = ( - 27 - 24,27)/10 = - 51,27/10 = - 5,127