5^x +5^y=3
5^x*5^y=2
5^x=a
5^y=b
a+b=3 a=3-b
ab=2
(3-b)*b=2
3b-b^2-2=0
b^2-3b+2=0
D=9-8=1
b1=(3+1)/2*1=4/2=2
b2=(3-1)/2*1=2/2=1
a1=3-2=1
a2=3-1=2
5^x1=1
5^x1=5^0
x1=0
5^x2=2
x2=log(5)2
5^y1=2
y1=log(5)2
5^y2=1
5^y2=5^0
y2=0
ответ: (0;log(5)2 ) , (log(5)2;0)
5^x +5^y=3
5^x*5^y=2
5^x=a
5^y=b
a+b=3 a=3-b
ab=2
(3-b)*b=2
3b-b^2-2=0
b^2-3b+2=0
D=9-8=1
b1=(3+1)/2*1=4/2=2
b2=(3-1)/2*1=2/2=1
a1=3-2=1
a2=3-1=2
5^x1=1
5^x1=5^0
x1=0
5^x2=2
x2=log(5)2
5^y1=2
y1=log(5)2
5^y2=1
5^y2=5^0
y2=0
ответ: (0;log(5)2 ) , (log(5)2;0)