Решите систему уравнений
{1/5 (x+y) = 2
{1/2 (x-y) = 1

1/5(x + y) = 21/2(x - y) = 11/5x + 1/5y = 21/2x - 1/2y = 10,2x + 0,2y = 20,5x - 0,5y = 10,2x + 0,2y = 2-0,5y = -0,5x + 10,2x + 0,2y = 2y = x - 20,2x + 0,2(x - 2) = 20,2x + 0,2x - 0,4 = 20,4x = 2,4x = 6y = 6 - 2y = 4

ответ: (6; 4).