Решите неравенства
|2x+1|<3
|3x-2|>7
|4x+3|≥5
|1-2x|≤5

юююю20 юююю20    2   19.02.2021 06:11    0

Ответы
Kotik210 Kotik210  21.03.2021 06:23

|2x+1|

x ∈ ( -∞ ; -2 )

|3x-2|7\\\\\left \{ {{3x-27} \atop {3x-2-7}} \right. \\\\\left \{ {{3x7+2} \atop {3x-7+2}} \right. \\\\\left \{ {{3x9} \atop {3x-5}} \right. \\\\\left \{ {{x9:3} \atop {x-5:3}} \right. \\\\\left \{ {{x3} \atop {x-1\frac{2}{3} }} \right. \\

x ∈ ( 3 ; +∞ )

|4x+3|\geq 5\\\\\left \{ {{4x+3\geq 5} \atop {4x+3\geq -5}} \right. \\\\\left \{ {{4x\geq 5-3} \atop {4x\geq -5-3}} \right. \\\\\left \{ {{4x\geq 2} \atop {4x\geq -8}} \right. \\\\\left \{ {{x\geq 2:4} \atop {x\geq -8:4}} \right. \\\\\left \{ {{x\geq 0,5} \atop {x\geq -2}} \right.

x ∈ [ 0,5 ; +∞ )

|1-2x|\leq 5\\\\\left \{ {{1-2x\leq 5} \atop {1-2x\leq -5}} \right. \\\\\left \{ {{-2x\leq 5-1} \atop {-2x\leq -5-1}} \right. \\\\\left \{ {{-2x\leq 4} \atop {-2x\leq -6}} \right. \\\\\left \{ {{x\geq 4:-2} \atop {x\geq -6:(-2)}} \right. \\\\\left \{ {{x\geq -2} \atop {x\geq 3}} \right.

x ∈ [ 3 ; +∞ )

ПОКАЗАТЬ ОТВЕТЫ
Другие вопросы по теме Математика