1)Δf=f(x0+Δx)-f(x0)=f(1+0.3)-f(1)=4-3*1.3-(4-3)=4-3.9-1=-0.9
2)Δf=0.5(-2+0.8)^2-0.5*(-2)^2=0.72-2=-1.28
1)Δf=f(x0+Δx)-f(x0)=f(1+0.3)-f(1)=4-3*1.3-(4-3)=4-3.9-1=-0.9
2)Δf=0.5(-2+0.8)^2-0.5*(-2)^2=0.72-2=-1.28