решить
1) (6x + 1) – (3 – 2x) = 14
2) (6 – 2c) + 4 = – 5c – 3
3) (10x–3) + (14x–4) = 8 – (15 – 22x)
4) (7–10k) – (8–8k) + (10k + 6) = – 8
5) 6y – 20 = 2(5y – 10) – 4y
6) (1 + 5v) = 5(1 + 6v)
7) 3,4 – 0,6b= 2b – (0,4b+ 1)
8) – 3(y + 2,5) = 6,9 – 4,2y
9) 4(1 – 0,5a) = – 2(3 + 2a)
10) 3(0,4x + 7) – 4(0,8x – 3) = 2

loooowaa    1   21.04.2020 11:48    0