Найти площадь фигуры, ограниченной графиком функции f(x)=4- x2 , прямой и осью ох.
Znanija1821
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31.07.2019 13:40
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1
4-х²=0
х²=4
х=-2
х=2
S=S(4-x²)dx=4x-x³/3|2-(-2)=8-8/3+8-8/3=16-16/3=32/3