x2−5x+6=0
(1)⋅x2+(−5)⋅x+(6)=0
x=−(−5)±(−5)2−4⋅(6)−−−−−−−−−−−−√2
x=5±25−(24)−−−−−−−−√2
x=5±1–√2
x=5±(1)2
x1=62=(2)⋅(3)(2)=3
x2=42=(2)⋅(2)(2)=2
наверн так
x2−5x+6=0
(1)⋅x2+(−5)⋅x+(6)=0
x=−(−5)±(−5)2−4⋅(6)−−−−−−−−−−−−√2
x=5±25−(24)−−−−−−−−√2
x=5±1–√2
x=5±(1)2
x1=62=(2)⋅(3)(2)=3
x2=42=(2)⋅(2)(2)=2
наверн так