√((1-4x+3)/(x²-x-12))
((1-4x+3)/(x²-x-12))≥0
1-4x+3=0⇒х=1
x²-x-12=0 по Виету х=-3; х=4
-314
+ - + -
х∈(-∞;-3)∪[1;4)
√((1-4x+3)/(x²-x-12))
((1-4x+3)/(x²-x-12))≥0
1-4x+3=0⇒х=1
x²-x-12=0 по Виету х=-3; х=4
-314
+ - + -
х∈(-∞;-3)∪[1;4)