Написать уравнение касательной к графику функции 1. f(x) = 5x3 - 2x2 x0 = 2

2 f(x) = - 3x3 + 3 x0 = - 1

3 f(x) = 4x3 - 2 x2 - 3x + 7 x0 = 0

4 f(x) = x3 - 3 x2 +1 x0 = 2

5 f(x) = 5x2 - 4 x x0 = 3

6 f(x) = - 3 x3 - 2 x2 + 1 x0 = 1

7 f(x) = x3 - 2 x + 1 x0 = 1

8 f(x) = 2 x2 - 4 x x0 = 2

9 f(x) = 3 x3 - 5 x0 = 0

10 f(x) = x3 - 2 x2 + 4 x0 = 1

11 f(x) = 2x4 - 3 x3 + 2 x x0 = -1

12 f(x) = -3 x5 + x4 x0 = 0

13 f(x) = - 3x4 +5 x3 - 2 x x0 = 2

Если можно в тетради

1Кat3    1   26.11.2020 20:03    1