Написать первых 7 членов последовательности {xn=(2n+5)/(3n+8)}

Х1=(2*1+5)/3*1+8)=7/11
х2=(2*2+5)/(3*2+8) = 9/14
х3 = (2*3+5)/(3*3+8) = 11/17
х4 = (2*4+5)/(3*4+8) = 13/20
х5 = (2*5+5)/(3*5+8) = 15/23
х6 = (2*6+5)/(3*6+8) = 17/26
х7 = (2*7+5)/(3*7+8) = 19/29