Log_12(2x-9)=1log_3(5x+3)= 1+3log_3 2

Question

Математика: Log_12(2x-9)=1log_3(5x+3)= 1+3log_3 2

леся546576 · Answer

log12(2x-9)=1log12(2x-9)-log12(12) 2x-9)log 12( ) 12log3(5x+3)=1+3 log3(2)log3(5x+3)=1+3log3(2), x - 3/5log3(5x+3)=log3(3)+log3(2³)log3(5x+3)=log3(3×2³)log3(5x+3)=log3(3×8)log3(5x+3)=log3(24)5x+3=245x=24-35x=21x= 21/5, x -3/5x=21/5...

Log_12(2x-9)=1

log_3(5x+3)= 1+3log_3 2

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