(x+y)(x+y+z)=7,
(y+z)(y+z+x)=8,
(z+x)(z+x+y)=9
==================
(x+y)(x+y+z)+(y+z)(y+z+x)+(z+x)(z+x+y)=7+8+9
выносим общий множитель
((x+y)+(y+z)+(z+x))(z+x+y)=24
(x+y+y+z+z+x)(z+x+y)=24
(2x+2y+2z)(x+y+z)=24
2(x+y+z)(x+y+z)=24
а значит
или
(x+y)(x+y+z)=7,
(y+z)(y+z+x)=8,
(z+x)(z+x+y)=9
==================
(x+y)(x+y+z)+(y+z)(y+z+x)+(z+x)(z+x+y)=7+8+9
выносим общий множитель
((x+y)+(y+z)+(z+x))(z+x+y)=24
(x+y+y+z+z+x)(z+x+y)=24
(2x+2y+2z)(x+y+z)=24
2(x+y+z)(x+y+z)=24
а значит
или