ДАМ 100б памагите со всем​


ДАМ 100б памагите со всем​

gyuzal1 gyuzal1    2   24.12.2020 21:38    0

Ответы
Ариана20031410 Ариана20031410  23.01.2021 21:42

1) C

2) \frac{4}{9}; 1\frac{1}{3}; 2\frac{5}{6}; \frac{20}{3}

3) x=\frac{14}{21}

4) \frac{24}{29}\\ кг

5) \frac{163}{216}

Пошаговое объяснение:

2) 4/3; 20/3; 17/6; 4/9 | 24/18; 120/18; 51/18; 8/18 | 8/18; 24/18; 51/18; 120/18

3) x+\frac{2}{21}-\frac{11}{21}=\frac{5}{21} \\\\x=\frac{5}{21}-\frac{2}{21}+\frac{11}{21}\\\\x=\frac{14}{21}

4) \frac{5}{8}+\frac{1}{6}+x=2\\\\\frac{15}{24}+\frac{4}{24}+\frac{24x}{24}=\frac{48}{24}\\15+4+24x=48\\24x=48-15-4\\24x=29\\x=\frac{29}{24}

5)(3\frac{5}{6}-1\frac{3}{4}):(5\frac{1}{8}+4\frac{7}{24})+(1\frac{1}{5}+2\frac{1}{6}+1\frac{19}{30})*\frac{1}{10}=\frac{\frac{23}{6}-\frac{7}{4}}{\frac{41}{8}+\frac{103}{24}}+(\frac{6}{5}+\frac{13}{6}+\frac{49}{30})*\frac{1}{10}=\frac{\frac{46}{12}-\frac{21}{12}}{\frac{123}{24}+\frac{103}{24}}+(\frac{36}{30}+\frac{65}{30}+\frac{49}{30})*\frac{1}{10}=\frac{\frac{25}{12}}{\frac{226}{24}}+(\frac{36}{30}+\frac{65}{30}+\frac{49}{30})*\frac{1}{10}=\frac{25*24}{12*226}+\frac{150}{30}*\frac{1}{10}\frac{25*24}{12*226}+\frac{150}{30}*\frac{1}{10}=\frac{50}{226}+\frac{5}{10}=\frac{50}{226}+\frac{1}{2}=\frac{50}{226}+\frac{113}{216}=\frac{163}{216}

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