x - 2y + 10 = 0
Пошаговое объяснение:
Let (x1;y1) = (6;8), (x2;y2) = (0;5)
Using the formula:
Convert it:
Substitute the values: (0 - 6)(y - 8) = (5 - 8)(x - 6);
-6(y - 8) = -3(x - 6)
-6y + 48 = -3x + 18
3x - 6y + 30 = 0
x - 2y + 10 = 0
Пошаговое объяснение:
Let (x1;y1) = (6;8), (x2;y2) = (0;5)
Using the formula:
Convert it:
Substitute the values: (0 - 6)(y - 8) = (5 - 8)(x - 6);
-6(y - 8) = -3(x - 6)
-6y + 48 = -3x + 18
3x - 6y + 30 = 0
x - 2y + 10 = 0