7*(4а^5+2аb)= (5xy-3x^2)*x^2= 2a^7*(5a^3+0,4ab)= (-2/11)*(m-n+p)= (-4)*(8a^2-6a+12)= (1,4x^2-3,5y)*(-2/7x)=

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Математика: 7*(4а^5+2аb)= (5xy-3x^2)*x^2= 2a^7*(5a^3+0,4ab)= (-2/11)*(m-n+p)= (-4)*(8a^2-6a+12)= (1,4x^2-3,5y)*(-2/7x)=

жалеоИвантелтуштуш · Answer

7 (4а⁵+2ab) = 28a⁵+ 14ab =
вынесем общий множитель (если нужно):
= 14a(2a⁴+b)

(5xy-3x²)*x²= 5x²⁺¹y -3x²⁺²=5х³y- 3х⁴=
= x³ (5y-3x)

2a⁷(5a³+0.4ab) = 2*5a⁷⁺⁴ + 2*0.4a⁷⁺¹ b= 10a¹¹ +0.8a⁸b=
= 10a⁸ (a³+0.08b)

(-2/11)(m-n+р) = - 2/11 m +2/11 n - 2/11 р

-4 (8а²-6а+12) = -32а² +24а - 48 =
=- 8(4а² +3а -6)

(1/4 х² -3,5у)(-2/7 х) = -(1/4* 2/7) х³ + (3,5 *2/7 ) х=-1/14 х³ + х=
= х ( -1/14 x² +1)

7(4а^5+2аb)= (5xy-3x^2)x^2= 2a^7(5a^3+0,4ab)= (-2/11)(m-n+p)= (-4)(8a^2-6a+12)= (1,4x^2-3,5y)(-2/7x)=

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