(125а +y) — 97 = 7
125a-97=7-y
125a=7-y+97
125a=104-y
\frac{125a}{125}=\frac{104-y}{125}
a=\frac{104-y}{125}
(125а +y) — 97 = 7
125a-97=7-y
125a=7-y+97
125a=104-y
\frac{125a}{125}=\frac{104-y}{125}
a=\frac{104-y}{125}