2(2x-1)^2+5(2x-1)-3=0 решите ,хотелось бы с !

2 ( 4х^2 - 4x + 1) + 10x -5 - 3 = 0
8x^2 - 8x +2 + 10x - 5 - 3 = 0
8x^2 + 2x - 6 = 0
4x^2 + x - 3 = 0
D = 1 - 4(4* -3) = 49  YD = 7
x1 =( - 1 + 7) / 8 = 6/8 = 3/4 = 0,75
x2 = ( - 1 - 7) / 8 = - 1
ответ: x1 = 0,75;  х2 = - 1