1) m-(5/8m-1/4m), ecли m = 16; 1 целая 3/5 2) 3 3/7x - (1 3/14 + 8/21x) x = 24; 2/11 3) a-(1/15a + 3/10a, ecли а= 30; 1 целая 11/19

hdhdydjsh hdhdydjsh    2   11.09.2019 21:30    1

Ответы
Gazeerovka Gazeerovka  07.10.2020 08:17
1) m-(5/8m-2/8m)=m-3/8m=8/8m-3/8m=5/8m 
5/8 *16=5*2=10
5/8*3/5=3/8

2)3 3/7x-(1 9/42x+16/42x) = 3 3/7x - 1 25/42x = 3 18/42x-1 25/42x= 2 60/42x-1 25/42x= 1 35/42x= 1 5/6x
1 5/6*24 = 11/6*24=11*4=44
1 5/6* 2/11 = 11/6*2/11=1/3

3) a-( 2/30a+9/30a) = a-11/30a=30/30a-11/30a=19/30a
19/30 * 30 =19
19/30* 1 11/19 = 19/30* 30/19=1
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