1) 52(x + y) – x +6 = 0, (3x – (x – y) = 0;
3) (5x – 2(y + 4) = 0,
6 (2x + 3) - y - 41 = 0;
2) 3(x + 2y) - y - 27 = 0,
4(x + y) – 3x – 23 = 0;
4) 2x + 3(x + y) - 11 = 0,
7 (x + 3y) - 6x + 59 = 0.​


1) 52(x + y) – x +6 = 0, (3x – (x – y) = 0;3) (5x – 2(y + 4) = 0,6 (2x + 3) - y - 41 = 0;2) 3(x + 2y

olgaversh olgaversh    1   29.04.2021 16:58    0

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