дано
m(C2H5OH) = 42 g
V(C2H4) - ?
C2H5OH-->C2H4+HOH
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m(C2H5OH) / M(C2H5OH) = 42 /46 = 0.91 mol
n(C2H5OH) = n(C2H4) = 0.91 mol
V(C2H4) = n(C2H4) * Vm = 0.91*22.4 = 20.384 L
ответ 20.384 л
Объяснение:
дано
m(C2H5OH) = 42 g
V(C2H4) - ?
C2H5OH-->C2H4+HOH
M(C2H5OH) = 46 g/mol
n(C2H5OH) = m(C2H5OH) / M(C2H5OH) = 42 /46 = 0.91 mol
n(C2H5OH) = n(C2H4) = 0.91 mol
V(C2H4) = n(C2H4) * Vm = 0.91*22.4 = 20.384 L
ответ 20.384 л
Объяснение: