AgNO₃ + HCl = AgCl + HNO₃
n(AgNO₃) = 1,7/170 = 0,01(моль)
n(AgCl) = n(AgNO₃) =0,01(моль)
m(AgCl) =0,01·143,5 = 1,435(г)
AgNO₃ + HCl = AgCl + HNO₃
n(AgNO₃) = 1,7/170 = 0,01(моль)
n(AgCl) = n(AgNO₃) =0,01(моль)
m(AgCl) =0,01·143,5 = 1,435(г)