first find the poh value:
poh=14-ph=14-11.2=2.8
then we apply the following formula:
poh=-lg(√Kb×c)
2.8=-lg(√6.3×10^-5×C)
C((ch3)3n)=0.04М
first find the poh value:
poh=14-ph=14-11.2=2.8
then we apply the following formula:
poh=-lg(√Kb×c)
2.8=-lg(√6.3×10^-5×C)
C((ch3)3n)=0.04М