W(c) =53.33% w(h) =15.56% w(n)=31.11% d(ne)=2.25 найти: cxhynz

CxHyNz = r

D(r)(Ne) = 2.25 ==> M(r) = 2.25 * 20 = 45 г/моль

n(C) = (53.33*45)/1200 = 2
n(H) = (15.56*45)/100 = 7
n(N) = (31.11*45)/1400 = 1

C2H7N;

NH2C2H5 — этиламин.